-32x^2-72x-40=0

Solution for -32x^2-72x-40=0 equation:

-32x^2-72x-40=0

a = -32; b = -72; c = -40;
Δ = b2-4ac
Δ = -722-4·(-32)·(-40)
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-72)-8}{2*-32}=\frac{64}{-64}
=-1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-72)+8}{2*-32}=\frac{80}{-64}
=-1+1/4
$